If you mean: y = 12x-23 then the slope is 12 and the y intercept is -23
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
So the given line is y=12x-8 and the given point is x=2 y=15? 15=12*2+m m=-9 y=12x-9
There is no y intercept and the slope of the line is 12 from the origin
None because without an equality sign the given expression is not an equation.
3x-15x-y= 45 -12x-y=45 -y=12x+45 y=-12x-45 Solution set: straight line, y-intercept=-45 and slope =-12
If the equation is y=12x, the slope is 12
If you mean y = 12x then the slope of the line is 12
35
y = 12x or y = 12x + 0 This equation is in the form of slope-intercept form, y = mx + b, where m is the slope. Thus, the slope is 12.
If you mean y = 12x then the slope of the line is 12
12
12
[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .
It is: y = 12x+4
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
Without an equality sign and not knowing some of the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean: y = 12x-3 a given point of (5, 0) Then the perpendicular equation is: y = -1/12x+5/12 whereas -1/12 is the slope and 5/12 is the y intercept
If you mean y = -12x+3 then it is a straight line equation whereas -12 is the slope and 3 is the y intercept