Q: What is the slope of the line joining 2 0 and 1 3?

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The slope of the line joining (0,3) and (3,0) is -1

Points: (0, 6) and (6,0) and the slope of the line works out as -1

Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.

Points: (0, 0) and (4, 1) Slope: 1/4

Points: (0, 0) and (4, 1) Slope: 1/4

If you mean points of (3, 1) and (0, -5) then the slope is 2

The question is not altogether clear because of the Answers browser. But: The slope of the line joining (5,4) and (0,3) is (4-3)/(5-0) = 1/5 or 0.2

Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.

Points: (-2, 1) and (0, -3) Slope: -2

1. The slope of a flat line is smaller than the slope of a steep line.2. The slope of a flat line should be close to 0. 3. A negative slope means that the line mover down from left to right.

The line perpendicular to a line with a slope of 1/5 has a slope of -5.

The slope is -2/6 = -1/3.

If you mean points of: (0, 5) and (10, 0) then the slope is -1/2

Points: (1, 5) and (0, 2) Slope: 3

Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2

The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.

The slope is 1/2.

If you mean points of (-10, 1) and (0, -4) then the slope works out as -1/2

The larger the absolute value of the slope if, the more vertical, or steeper, the line is. A horizontal line has slope 0, a line that is just a very little bit steep, might have slope, 1/10, a line that is very steep might have slope 10/1 or 10, or even 1000000 and as that number gets bigger and bigger, the line becomes almost vertical. For practical purposes, the slope, or steepness, of the line can be determined by rise over run, or, with a 0/0 intercept, then y over x, or, y1-y2 over x1-x2.

(0, 0) and (-2 -2) -2-0 divided by -2-0 which gives a slope of 1

Slope is the change in y/change in x.So slope of the line passing through the points: (2,-1) & (0,4) isslope = [-1 - 4] / [2 - 0] = -5/2

If the line has a slope of 2, then the perpendicular line has a slope of -1/2. The slope of a perpendicular line is the negative reciprocal. Another example would be if the slope of a line is -1/4, then the slope of the perpendicular is 4.

M (slope) = (Y2 - Y1) / (X2 - X1) You need two points on a graph to make it a line. If point A is at (0,0) and point B is at (1, 1) then your slope would be M = (1 - 0) / (1 - 0) = 1 / 1 = 1

Points: (2, 5) and (-1, 5) Slope: 0 and so therefore it has no slope but is a straight line parallel to the x axis

Slope = (4-3)/(5-0) = 1/5

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