0
between points (x0, y0) and (x1, y1):
slope = change_in_y/change_in_x
→ slope = (y1 - y0)/(x1 - x0)
→ slope = (3 - 0)/(1 - 2) = 3/(-1) = -3
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What is the equation in slope intercept form of the line joining the points -2.5 -0.5 and 4.5 -1?
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form
If one slope is -1 what is the slope of the perpendicular slope?
The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.
What is the equation of the straight line extending from the origin to the midpoint of the line joining 3 2 and 5 -1?
1st find the midpoint -- (4, 1/2) Now slope -- 1/2 divided by 4 = 1/8 y-intercept = 0 (origin) y = (1/8)x <--- answer
What is a Equation of a vertical line?
m=1/0 The m(slope) is 1/0 because it is rise over run. The line is "rising" but not "running".
What is the slope of the line passing through points a 5 4 and b 0 3?
Slope = (change_in_y) / (change_in_x) = (4 - 3) / (5 - 0) = 1/5 = 0.2
What would be the slope for 0 3 and 3 0?
The slope of the line joining (0,3) and (3,0) is -1
What is the slope of a line that goes through (0 6) and (6 0)?
Points: (0, 6) and (6,0) and the slope of the line works out as -1
What is the slope of 54 and 03?
The question is not altogether clear because of the Answers browser. But: The slope of the line joining (5,4) and (0,3) is (4-3)/(5-0) = 1/5 or 0.2
What is the slope of the line that passes through (0 0) and (4 1)?
Points: (0, 0) and (4, 1) Slope: 1/4
What is the slope of the line that passes through (4 1) and (1 0)?
Points: (0, 0) and (4, 1) Slope: 1/4
Find the slope of the line that passes through these points -1 -1 and 0 0?
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
What is the slope of the line that contains the points (-2 1) and (0 -3)?
Points: (-2, 1) and (0, -3) Slope: -2
What is the equation of a line that passes through the point 0 2 and is perpendicular to a line with a slope of 3?
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
Slope of a line 31 and 0-5?
If you mean points of (3, 1) and (0, -5) then the slope is 2
Find the slope of the line passing through (1 5) and (0 2).?
Points: (1, 5) and (0, 2) Slope: 3
What is the slope of the line with points 2 -1 and 0 4?
Slope is the change in y/change in x.So slope of the line passing through the points: (2,-1) & (0,4) isslope = [-1 - 4] / [2 - 0] = -5/2
Q and -q are two charges d distances apartFind locus of a point at which electric fields are parallel to the line joining the charges?
Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.
