Points: (5, -1) and (2, -5)
Slope: 4/3
Perpendicular slope: -3/4
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
The slope is -9.
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
1:5
Since the line is horizontal, the slope is zero.
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
Infinite. The line is perpendicular to the ordinate.
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
The slope is -9.
Another set of points are needed to find the slope.
The slope is -9.
17
That depends on the points in order to find the slope whereas no points have been given.
Points: (3, 4) and (2, 1) Slope: 3
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
thanks you for your help
If the line passing through these points is a straight line then it has a positive gradient.