From the given points the slope of the line works out as 3/4
A line with the equation:x = a constant valueis a vertical line. Examples of such a line are x = 3, x = 5, x = 10, x = -4.The slope of a vertical line is infinite.
I believe the slope would be: -4 / 3
12
The slope is (9 - -1)/(2 - 4) = 10/-2 = -5
it's 4/7 And you need to write the questions like this: "Find the slope of the line pasing through (3,4) and (10,8)"
Answer:-10/2=-5Solution:The relation between the line slope and it's perpendicular line slope is negative reciprocal, i.e.Slope of the line perpendicular = -1/Slope of the line= -1/(2/10)= -1 x 10/2= -10/2= -5
It has infinite slope.
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
10
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
a like that is parallel to the line y - 5x = 10 will have the same slope as y - 5x = 10. the slope of a line is determined by the standard form of a linear equation y = mx + b where m is the slope. we need to get our equation to look like the standard form. y - 5x = 10 y = 10 + 5x (adding 5x to both sides) comparing this to our standard form y = mx + b the number in front of the x is our slope. in this particular equation m = 5 the slope of a like parallel to this line will be the same, a slope of 5
y = 7x-10
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
If you mean point of (1, 4) and slope of -10 then y = -10x+14
The larger the absolute value of the slope if, the more vertical, or steeper, the line is. A horizontal line has slope 0, a line that is just a very little bit steep, might have slope, 1/10, a line that is very steep might have slope 10/1 or 10, or even 1000000 and as that number gets bigger and bigger, the line becomes almost vertical. For practical purposes, the slope, or steepness, of the line can be determined by rise over run, or, with a 0/0 intercept, then y over x, or, y1-y2 over x1-x2.
They determine the equation of a nonvertical line in the slope-intercept form, y = 3x - 10.