Top Answer

A number which is divisible by both 2 & 3 is a multiple of 6 i.e. the number is divisible by 6.

So, we need to find out the smallest 5 digit number divisible by 6(or 2 & 3).

Smallest 5 digit number = 10000

Dividing 10000 by 6, we get

10000 = 6 x 1666 + 4

9996 = 6 x 1666

If we add 6 to 9996 we obtain a number which is divisible by 6.

6 + 9996 = 10002(divisible by 6).

So, the smallest five digit number divisible by 6 is 10002.

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Here is another one that's smaller than 10,002 and satisfies

the other specifications stated in the question:

6.0000

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A number is divisible by 2 if it is an even number. That is, if the last digit is divisible by 2.

smallest 4-digit number divisible by 2 = 1000

1002 is the smallest 4 digit number divisible by 3 and 2.

12 is the smallest 2 digit number divisible evenly by 4

There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.

yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6

Yes. 72 divided by 2 is 36. To find out if a number is divisible by 2 look at the last digit of the number. If it is even then the number is divisible by 2. For example 86 the lst digit is 6 which is an even number which means it is divisible by 2. yes, any even number is divisible by two.

if the last digit is even or 0, a number is divisible by 2!

I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I

There is no 4-digit number that is divisible by zero.

If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.

. . . an even number.

2,4,6,8

Look at the last digit of the number; if it is even then the number is divisible by 2, otherwise it is not.

Yes. If the last digit is even (ie one of 0, 2, 4, 6, 8) then the whole number is divisible by 2. The last digit is 4, so the number is divisible by 2.

100

The number 100,002 is divisible by 3. The largest 5 digit number is 99996 (6 less).

1000 is the smallest 4 digit number but of the two factors, it is only divisible by 2. As 999 is obviously divisible by 3 then 999 + 3 = 1002 is also divisible by 3 and, as an even number, is also divisible by 2. The answer is 1002

There is no number, no matter the number of digits, that is only divisible by 2.

An even number, by definition is divisible by 2. For the number to be divisible by 10, the last digit must be 0, which ensures it is an even number. Any number, with zero as the last digit will satisfy the requirements. So 111110 will do.

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

Not evenly because it will have a remainder of 1

No, any whole number ending in a digit divisible by 2 is also divisible by 2 and therefore not a prime number.

If the last digit of a number is 0, 2, 4, 6, 8 or 0 then the number is divisible by 2. The digit of 619 is 9, so 619 is not divisible by 2.

Yes. To be divisible by 2, the last digit must be divisible by 2, ie an even digit. The even digits are {0, 2, 4, 6, 8} (and the odd digits are {1, 3, 5, 7, 9}) the last digit of 93703542 is 2 which is an even digit, thus the number is divisible by 2.