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Let x be the 1st odd integer, then the next three odd integers are x+2, x+4, and x+6

x+(x+2)+(x+4)+(x+6) = 968

4x+12 = 968

4x = 956

x = 239

so the 4 consecutive odd integers are 239, 241, 243, 245

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12y ago
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Q: What is the smallest of four consecutive odd integers whose sum is 968?
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