sq. root of 75 = sq. root of (25 x 3) = (sq. root of 25)(sq. root of 3) = 5(sq. root of 3)
sq. root of (80/125)= sq. root of [(9)(2)(5)/(25)(5)]= (sq. root of 9)(sq. root of 2)/sq. root of 25= (3/5)sq. root of 2
let x = 1st number, then 19 - x = 2nd number 120 = x(19 - x) x2 -19x +120 = 0 use quadratic formula to solve x = (19 +/- sq rt(361 - 480))/2 x = (19 + sq root (-119))/2 or x = (19 - sq root (-119))/2 '''x = 19/2 + ''i''(sq rt 119) /2 and''' '''x = 19/2 - ''i''(sq rt 119) /2''' there are no real solutions, both are imaginary. Actually they are complex conjugates.
11.18033989 is the sq. root of 125.
sq root (112.7) = 10.6160256.... sq root (112.7) = 10.6160256....
4
It is the square root of 30
Sq root of 2 * sq root of 8 = 1.414 * 2.828 = 3.998792
Find the factors of 484484= (4)(121)Square root of (484) = Sq. root (4 x 121) = Sq. root (4) x sq. root of (121) = 2(11) = 22
Square root of 6 = 2.44948 Sq root of 6 + Sq root of 6 = 2.44948 + 2.44948 = 4.89896
3.5714
Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36