√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
The real equation got messed up when I posted it, the real equation is this: 2x^3 - 11x^2 + 24x - 18 divided by 2x - 3 ^ = to the 3rd and 2nd power.
33
-12 +/- sq root 104
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
(x^2) + 24x + 144 = -9 x = -12
The answer is, 24x
2√6x
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
12
-60
x(x3 - 24x - 22)
The real equation got messed up when I posted it, the real equation is this: 2x^3 - 11x^2 + 24x - 18 divided by 2x - 3 ^ = to the 3rd and 2nd power.
yes
33
false!
-12 +/- sq root 104
3x