194
194
The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5
The square root of 8 over 25 is irrational, and real.
13. The figures provided (including the answer) satisfy Pythagoras' Theorem. a2 = b2 + c2 a2 = 52 + 122 = 25 + 144 = 169 Then a = √169 = 13
194
194
That depends where you are placing the brackets. sqrt(169 - 25) = sqrt(144) = 12, however, sqrt(169) - 25 = 13 - 25 = -12.
If the 13 was the long side (hypoteneuse), the other side would be the square root of 13²-5² = square root of 169-25 = square root of 144 = 12. (according to Pythagoras). If the 13 was a short side, the other is square root of 13² + 5² = square root of 169+25 = square root of 194, or about 13.93
The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5
The square root of 8 over 25 is irrational, and real.
the square root of 122+52 (144 + 25 = 169) which is 13.
√4225 = √(25)(169) = √(5^2)(13^2) = 5 x 13 = 65
13. The figures provided (including the answer) satisfy Pythagoras' Theorem. a2 = b2 + c2 a2 = 52 + 122 = 25 + 144 = 169 Then a = √169 = 13
1.6
The square root of 25 is 5 ... rational.
It is: 5/9