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1.4142135 is the square root of 2 1.7320508 is the square root of 3 2.0000000 is the square root of 4

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hmm... okay, if I understand you correctly, 2 times the square root of 3 times the square root of 12? = 2(1.73)(3.46) = 11.9716. If you aren't using the approximations, then just simplifying is... [sorry, I can't do the square root sign on the computer...] 2(square root of 3)(square root of 12) = 2(square root of 3)(square root of 4*3) = 4(square root of 3)(square root of 3) = 4(3) = 12!!! HOPE I HELPED!! :-)

2 times the Square root of 3 + 4

1.3333

2 root 3 over 2, so square root of 3

The square root of 12 equals the square root of 4 times 3. The square root of 4 is 2. The square root of 12 equals 2 times the square root of 3.

sqrt(4) = 2 sqrt(9) = 3 Therefore, the square root of 4 plus the square root of 9 is equal to 2 + 3 = 5.

(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2

It is: (3*2)-(2*2) = 2

The square root of the fraction 4/9 is either 2/3 or -2/3

6 Square root of 4 equals 2 3 x 2 = 6

x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.

(3 x 2) - (2 x 2) = 2

5 square root 7 because 3 square root of 28 goes from 3 square root of 28 to 3 square root of 7 and 4 which then 4 condenses down to 2 and you add that to 3 then you get 5 square root of 7

the square root of 4 is 2 square root 2

Square root 2 is the square root of 4 3 is the square root of 9 and so on

4

To simplify the square root of 12: Look at numbers that can be reduced from the larger number and can be square rooted itself. 4 * 3 = 12 The square root of 4 is 2. Therefore the simplification of the square root of 12 is: 2*square root of 3

The even-ness of the number is not relevant. The square root of 1, 4, 9 and 16 are 1, 2, 3 and 4, because 1*1 is 1, 2*2 is 4, 3*3 is 9 and 4+4 is 16. The numbers in between are irrational: The square root of 2 is 1.4 and a bit, the square root of 3 is 1.7 and a bit.

√3 / √(-32) = √(-3 / 32) = √(-3 / 2) / 4 = i√(3/2) / 4

4 square root 3 + 4 cube root 3 is 12.6972015

They all have square roots. Square root of 1 is 1 Square root of 4 is 2 Square root of 9 is 3

The Square-Root of 4 is 2 or -2.

x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:

Other than by calculating the square roots and adding the results there is no general method. However, by factorising the number (of which the square root is being taken), the square root can be simplified which may let the square root be added. Examples: √2 + √8 = √2 + √(4×2) = √2 + √4 × √2 = √2 + 2√2 (1 + 2)√2 = 3√2 √12 + √27 = √(4×3) + √(9×3) = 2√3 + 3√3 = 5√3 (Remember that the radical sign (√) means the positive square root.)

No. to be a perfect square, you have to be able to square root it and get a whole number (NOT a decimal) the square root of 3 is 1.732. (1.7322 = 3) a perfect square is a number like 4 the square root of four is 2 (22 = 4)