Q: What is the square root of eight divided by two to the second power?

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eight to the second power equal to 64

0.8 divided by 10 to the second power = 0.08

486

12 divided by 3 to the second power with work = 4

negative eight plus two times four to the second power

2x 2x to the second

10

24u to the second power. Differentiate 40u to the fifth power which is 200u to the fourth power and 5u to the second power which is 10u. Subtract 400u to the sixth power from 1000u to the sixth power which is 600u to the sixth power. Then square 5u to the second power which is 25u to the fourth power. Finally, divide 600u to the sixth power by 25u to the fourth power. The solution is 24u to the second power. Another method is simplifying it to 8u cubed (to the third power) and taking the power rule. Take 3 times 8u which is 24u and subtract 1 from 3 in exponent which is 2. The answer is 24u to the second power.

When you multiply a number by itself, you get the "second power" of the number.That's also called the "square" of the number.Here are some examples:The second power of 5 is (5 x 5) = 25.The second power (square) of 10 is (10 x 10) = 100.The square (second power) of 6 is (6 x 6) = 36.The square of 3.1 is (3.1 x 3.1) = 9.61.

square root of c to the second power is c

2

It is negative one divided by 4 multiplied by x to the power of 1.5 -1/(4(x^1.5))

5

115

1.3333

In classical times, the second power was described in terms of the area of a square. This led to the use of the term squareto mean raising to the second power.

1.75

It is a foot to the second power

they cancel each other out. the square root of 5 raised to the second power = 5

1 divided by 25 multiplied by z to the third power

2 to the second power is 4, which isn't a factor of 54. 3 to the second power is 9, which is a factor of 54 but isn't prime. 4 divided by 9 is 4/9, which isn't prime and isn't a factor of 54.

0.06

20.8

The square root of x squared is x, or x to the first power.

The common term for raising a base to the second power is to square it.Base^2