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What is the standard form of the equation of the conic section given below x2-y2-6x-2y 60?
Wiki User
∙ 10y ago
Assuming the equation is x2 - y2 - 6x - 2y = 60
this is equivalent to
x2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1
= (x - 3)2 - (y + 1)2 = 68
Assuming the equation is x2 - y2 - 6x - 2y = 60
this is equivalent to
x2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1
= (x - 3)2 - (y + 1)2 = 68
Assuming the equation is x2 - y2 - 6x - 2y = 60
this is equivalent to
x2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1
= (x - 3)2 - (y + 1)2 = 68
Assuming the equation is x2 - y2 - 6x - 2y = 60
this is equivalent to
x2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1
= (x - 3)2 - (y + 1)2 = 68
Wiki User
∙ 10y ago
Wiki User
∙ 10y agoAssuming the equation is x2 - y2 - 6x - 2y = 60
this is equivalent to
x2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1
= (x - 3)2 - (y + 1)2 = 68
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