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Q: What is the sum of 1-99?

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...int sum = 0;for (int i = 101; i

299

199 31+37+41+43+47=199

200

How about: 199+5 = 204

199, 200, 201

The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)

1 + 2 + 3 + ... + 199 + 200 + 199 + ... + 3 + 2 + 1 = 40000

The least of the three numbers is 199.

199

199 + 199 + 199 + 199 + 99 + 99 + 99 = 1192

199 If it's 200 rounded to nearest ten, then the number must be between 195 and 205. Only 199 has the correct digit sum.

199% = 1.99 = 199/100 = 199/100

199 is the absolute value of 199.

199 - 9% = 199 x (1 - (9/100)) = 199 x 0.91 = 181.09.

199,200 and 201 because 199+200+201=600

1 and 199

1 and 199

20% off 199:= 20% discount applied to 199= 199 - (20% x 199)= 199 - (0.20 x 199)= 199 - 39.80= 159.20

The multiple of 3 nearest to and below 1000 is 999. 999/3 = 333 The sum of all the multiples is 3 x 333 x 334/2 = 166833 The multiple of 5 nearest to and below 1000 is 995. 995/5 = 199 The sum of all the multiples is 5 x 199 x 200/2 = 99500

.199.

199 p - 408 = -209

No, 199 is a prime number.

199 = CXCIX

199 is.