10x20 + 5x10
=200 + 50
=250
620 is the sum of 5 x 100 and 12 x 10. But a real number in the decimal system cannot have a "12" as a tens digit.
5/10 - 3/10 = 2/10 = 1/5
8 (sum means add 2x10 +10x2 =40 then divide by 5 to find the amount of fives that fit=8)
The sum is 50+20 = 70
5*10 = 50
25 tens, or 250
5/10 - 3/10 = 2/10 = 1/5
620 is the sum of 5 x 100 and 12 x 10. But a real number in the decimal system cannot have a "12" as a tens digit.
1 − (2 × 10 + 8 × 5) = -59
8*10 plus 5*10 = 130
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
"The hundreds and the ones are the same digit and their sum is 10" did you say ?Well then, the hundreds and ones digit are both 5.And the tens is 2 less than that, or 3.So the number is . . . . . 535
There are five tens in 50 expression 10 x 1 = 10 10 x 2 = 20 10 x 3 = 30 10 x 4 = 50
What is the sum of 5 and 10 added to the product of 5 and 10
8 (sum means add 2x10 +10x2 =40 then divide by 5 to find the amount of fives that fit=8)
The sum is 50+20 = 70
5*10 = 50