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25 tens, or 250

There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }

You can't subtract 15 ones from 15 tens. The bills are all tens, so you'd have to get change first. Then you'd be subtracting 15 ones from 13 tens and 20 ones, or from 13 tens, one 5, and 15 ones.

11 tens + 5 ones = 115

"The hundreds and the ones are the same digit and their sum is 10" did you say ?Well then, the hundreds and ones digit are both 5.And the tens is 2 less than that, or 3.So the number is . . . . . 535

10 or 5

275 = Ones275 = Tens275 = Hundreds2 + 5 = 7275

6 ones and 5 tens

45 and the nearest ten to 45.23 is 45.20

16 tens= 16 * 10= 160 5 ones= 5 * 1= 5 160 + 5= 165

254 - has 2 hundreds, 5 tens, and 4 ones

There are 5 'tens' in the number 55 & 5 'ones'

7 tens and 4 ones 5 thousandths = 74.005

The sum of -5 and 20 is 15. The distance between -5 and 20 is 25. The sum of the numbers between -5 and 20 is 180. The sum of the numbers from -5 to 20 is 195.

9 tens = 90. 4 fewer ones than tens = 9 - 4 = 5. Therefore the answer is 95.

It has 2 ones and 5 tens

35 tens 35 ones

5, with 9 ones left over.

Split strategy is used to help in mental arithmetic, so in your head to do a sum such as 25+36 you split it into easier chunks of tens and ones 20+30+5+6 =50+11 =61

49

51

12

105 is.

50

the tens place is on the left for example the # 15 1 is the tens and 5 is the ones