(4 x 9) + (5 x 9) = (9 x 9)c= 81
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
8+y is the sum of 8 and y
The distributive property is: a ( b + c) = ab + ac so you need a sum. Remember that 44 is 40 + 4, that is your sum. so... 9 x 44 = 9 (40 + 4) = (9 x 40) + (9 x 4)
The sum of 9 and 5 is 14
(4 x 9) + (5 x 9) = (9 x 9)c= 81
45
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
"the same as the others added together" For example: a=b+c+d a is equal to the sum of b plus c plus d. 9=2+3+4
The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.
8+y is the sum of 8 and y
J C Sum was born in 1976.
The sum of 9 and 5 is 14
The sum of 19 and 9 is 28.
The distributive property is: a ( b + c) = ab + ac so you need a sum. Remember that 44 is 40 + 4, that is your sum. so... 9 x 44 = 9 (40 + 4) = (9 x 40) + (9 x 4)
The sum of 1 + 8 is 9.
The sum of 14 and 9 is 23.