10,341
S = 955 This is an arithmetic sequence, and the sum of an arithmetic sequence can be calculated as: S = n/2 x (U1 + Un) U1 is the first term (in this case 91) and Un is the last term (in this case 100). n presents the total number of terms in the sequence There are 10 numbers in this sequence (91, 92, 93, 94, 95, 96, 97, 98, 99, 100) So, the sum is : S = 10/2 x (91+100) = 955
The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.
Arithmetic : (First term)(last term)(act of terms)/2 Geometric : (first term)(total terms)+common ratio to the power of (1+2+...+(total terms-1))
if repeating is allowed... 36 (6x6, for the last two digits) If not, 6 (3x2, last two digits)
Hannah stern
6
The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.
Use arithmetic sequence which is adding the same every time. Then go for multiplier sequence and last exponential.
Given an arithmetic sequence whose first term is a, last term is l and common difference is d is:The series of partial sums, Sn, is given bySn = 1/2*n*(a + l) = 1/2*n*[2a + (n-1)*d]
875
The set of odd numbers is an arithmetic sequence. Let say that the sequence has n odd numbers where the first term is a1 and the last one is n. The formula to find the sum on nth terms for an arithmetic sequence is: Sn = (n/2)(a1 + an) or Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference that for odd numbers is 2. Sn = (n/2)(2a1 + 2n - 2)
first you jump to the last plant then the first plant then the last plant
connectors of sequence
In a story sequence words can be first, second, then, next, and last
S = 955 This is an arithmetic sequence, and the sum of an arithmetic sequence can be calculated as: S = n/2 x (U1 + Un) U1 is the first term (in this case 91) and Un is the last term (in this case 100). n presents the total number of terms in the sequence There are 10 numbers in this sequence (91, 92, 93, 94, 95, 96, 97, 98, 99, 100) So, the sum is : S = 10/2 x (91+100) = 955
A geographic sequence is a series of numbers that are ordered in sequence or as part of a special series. A geographic sequence must contain a first and last term.
The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.