Wiki User
∙ 13y agoThis is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996).
The sum of a series is:
S = (first + last) x number_of_terms / 2
For for 1-10000, the sum is:
S1 = (1 + 10000) x 10000 / 2
= 10001 x 5000
= 50005000
For the multiples of 7 the sum is:
S2 = (7 + 9996) x 1428 / 2
= 10003 x 714
= 7142142
So the sum of all integers not greater than 10000 that are not divisible by 7 is:
S = S1 - S2
= 50005000 - 7142142
= 42,862,858
Wiki User
∙ 13y agoWhat for? There is only a 154 inside that is divisible by 77...
There are 90 integers less than 1,000 that are divisible by 11.
There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11
Any integer that is divisible by 2 with no remainder is even otherwise it is an odd integer
666 integers.
It is 83667.
All integers greater than one are divisible by prime numbers.
What for? There is only a 154 inside that is divisible by 77...
There are 90 integers less than 1,000 that are divisible by 11.
There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11
Any integer that is divisible by 2 with no remainder is even otherwise it is an odd integer
There are no negative integers greater than five.
One less than 10000.
For example, for all numbers between 101-200: for (int i = 101; i
666 integers.
9 is greater than 6 and divisible by 3.
There are 544 positive integers less than 1,000 that are either divisible by two or by 11.