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Q: What is the sum of all numbers between 1 and 100 which are divisible by 2?

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All numbers that end in 0 or 5.

All of them are, but only 33 are evenly divisible by 3.

101

All of them are divisible by 1.

They are all the numbers of the form 1n5 where n is any integer.

100, 200, 300 and so on. All numbers ending with "00".

All integers are evenly divisible by 1.

There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.

They are all the multiples of 12 and there are 8 of them

Just one by all three.

-- All of the numbers that end with a zero are divisible by 10.-- All of those, and all of the numbers that end with a 5, are also divisible by 5.

-- All of the numbers that end with a zero are divisible by 10.-- All of those, and all of the numbers that end with a 5, are also divisible by 5.

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