You need to add all the numbers from 10 to 99. You can do that quickly with the formula for an arithmetic series.
Alternately, as 11+99=110 and all pairs of such numbers (11+98 to 55+56) all equal 110 (technically 10+n +99-n = 110 where n=1 to 45) the sum of all 45 of these sets must be 45x110 or 49,500
4,905
105 is the sum
Smallest will be 10 Biggest will be 99
All of the odd numbers between 11 and 99 inclusive are two digit numbers that are not multiples of 2. There are 45 of them.
100
For the tens digit to be a prime number then it must equal 2, 3, 5 or 7. There are four 3-digit prime numbers that fit the above condition and also have the tens and units digits forming a 2-digit prime number. 131, 137, 173, 179. The person supplying the question may like to sum the various combinations.
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
945
two consecutive 4- digit numbers have a sum of 9173.what are the numbers?
There are five such numbers.
It is not clear what the question means: there are 31 2-digit numbers that can be expressed as a sum of two squares.
The sum is 22 times the sum of the three digits.
There are three such numbers: 12, 24 and 36.
For a 2-digit prime number (which are all odd) to be the sum of two prime numbers, one of the prime numbers will have to be 2. That means the difference between the sum and the other addend will have to be 2. Prime numbers that differ by 2 are called twin primes. There are six pairs of 2-digit twin primes. Your numbers are 13, 19, 31, 43, 61 and 73.
2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.
Add the two greatest possible four digit numbers. 9999 + 9999
No two digit prime number exists that is a multiple of 7. All two digit numbers that are multiples of 7 are compositenumbers.
2,4,6,8,10,12,14,16,18