The 8 exterior angles of a regular octagon add up to 360 degrees
The exterior angle of a general octagon is any angle less than 180 degrees. The sum of the exterior angles of a polygon is 360 degrees. If the octagon is regular, then each of its 8 exterior angles is equal to 360/8 = 45 degrees.
Each interior angle of an octagon is 135o. The sum of the exterior angles of a polygon is 360o. A regular octagon has equal angles, thus: 8 x exterior_angle = 360o ⇒ exterior_angle = 360o ÷ 8 = 45o The interior and exterior angles of a polygon are supplementary, that is sum to 180o. interior_angle + 45o = 180o ⇒ interior_angle = 180o - 45o = 135o.
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
360 degress which is the same as the sum of the interior angles of a quadrilateral. 360 + 8 x 180 = 1800°
Any shape can have an exterior angle of 45 degrees. If you are talking about exterior angle sum, it is always 360 degrees for any polygon. If you are talking about a regular polygon (equal exterior angles), it would be 360/45=8 sides. Therefore, a regular octagon has exterior angles of 45 degrees.
Assuming you mean "what is the size of the exterior angle of a regular octagon", then: The sum of the exterior angles of any polygon is 360o. Thus for a regular octagon, each is 360o ÷ 8 = 45o.
The sum of the measures of the exterior angles of an octagon (and any polygon) is 360o.
360 degrees * * * * * No, that is the sum of the Exterior angles. The sum of the interior angles is 180*(8 - 2) = 180*6 = 1080 degrees.
The exterior angle of a general octagon is any angle less than 180 degrees. The sum of the exterior angles of a polygon is 360 degrees. If the octagon is regular, then each of its 8 exterior angles is equal to 360/8 = 45 degrees.
Sum of angles in a regular polygon = (#sides - 2) * 180. Sum of Octagon angles = (8-2) * 180 = 1080
Each interior angle of an octagon is 135o. The sum of the exterior angles of a polygon is 360o. A regular octagon has equal angles, thus: 8 x exterior_angle = 360o ⇒ exterior_angle = 360o ÷ 8 = 45o The interior and exterior angles of a polygon are supplementary, that is sum to 180o. interior_angle + 45o = 180o ⇒ interior_angle = 180o - 45o = 135o.
The sum of the exterior angles of any regular polygon is 360°
The sum of the exterior angles of any polygon is 360 degrees.
The sum of the exterior angles of any polygon is 360o.
A regular octagon. Since the exterior angle is 45 degrees and the sum of all exterior angles of any polygon is 360 degrees, then 45⁰n = 360⁰ n = 8
Exterior angles = 360 degrees Interior angles = 1080 degrees
What is the sum of the measures of the exterior angles of a regular polygon with ten sides