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What is the sum of first six terms of a sequence whose nth term is 4n-2?
Wiki User
∙ 15y ago
The first 6 terms would be when n is 1, 2, 3, 4, 5, and 6. And since the nth term is 3 - 4n, you would simply substitute the first six numbers for n:
* n = 1; 3 - 4(1); 3 - 4; -1 * n = 2; 3 - 4(2); 3 - 8; -5 * n = 3; 3 - 4(3); 3 - 12; -9 * n = 4; 3 - 4(4); 3 - 16; -13 * n = 5; 3 - 4(5); 3 - 20; -17 * n = 6; 3 - 4(6); 3 - 24; -21 -1, -5, -9, -13, -17, -21
Wiki User
∙ 15y ago
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What is the sum of first six terms of a sequence whose nth term is 8 - n?
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
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nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
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We need help with answering this question.
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the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
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