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It is mA + mB
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What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
How do you find the slope intercept form from 2 set of points?
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
What is the sum of b and 5?
(b+5)
What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
How do you change point-slope to slope-intercept?
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
How do you find the x intercept when you have slope and a point?
Obtain the coordinates of the point (a,b) Utilise the standard equation for a straight line y = mx + c The slope 'm' is known. Substituting a, b for x, y then b = ma + c : c = b - ma The equation now becomes y = mx + (b - ma) The x intercept occurs when y = 0 : substituting this gives :- 0 = mx + (b - ma) : mx = ma - b : x = (ma - b) ÷ m EXAMPLE : Slope is 5, Point coordinates are (2,4): x intercept = [(5 x 2) - 4] ÷ 5 = 6 ÷ 5 = 1.2
The sum of 38 and m?
Sum = 38 + M
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
How do you Work out average speeds for drag cars?
You record the various speed on the same distance and sum it. Then divide that sum with how many times you record it. Like for x meters : 1. a m/s 2. b m/s 3. c m/s . . n. y m/s The average would be : (a+b+c +...y)/n
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
what id the sum of m and 6?
The sum of "m" and 6 is "m + 6".
How do you find the slope intercept form from 2 set of points?
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
The sum of 3 times m and n?
the sum of 3 times m and n
Rearrange F equals ma?
F = MA M = F / A A = F / M
What about nested for loop?
Possible. Example: void mat_mul (int m, int n, int l, const int **a, const int **b, int **c) { int i, j, k; double sum; for (i=0; i<m; ++i) { for (j=0; j<l; ++j) { sum= 0; for (k=0; k<n; ++k) { sum += a[i][k] * b[k][j]; } c[i][j]= sum; } }
