Q: What is the sum of the 3rd and 5th term in the sequence where the nth term is 3n-4?

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That depends what the pattern of the sequence is.

0.16

As you are taking 3 away each time, the 5th term will be -5.

Nth number in an arithmetic series equals 'a + nd', where 'a' is the first number, 'n' signifies the Nth number and d is the amount by which each term in the series is incremented. For the 5th term it would be a + 5d

If you mean: +3 +1 -1 -3 then it is -5

1 1 2 3 5 etc start with 1 and 1 and to get the 3rd term 1+1 = 2 add 2nd and 3rd term to get 4th --- 1 + 2 = 3 add 3rd and 4th term to get the 5th --- 2 + 3 = 5 etc

Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)

56

If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46

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This is arithmetic progression with common difference of minus three...Formula:First Term +[ (number of term you want-1)*(common difference which is negative 3)]ExampleFor the 3RD term: -5=1+[(3-1)*(-3)]=1+[-6]= -5For 5TH term: -11=1+[(5-1)*(-3)]=1+(-12)=-11.: For the 21st term:=1+[(21-1)*(-3)]=1+[-60]= -59:D

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first you need to write your equation. This is an exponential function so the equation would be- A(N)=a(b)^n-1 where a is the first term in the sequence (for you a=-14) b is the common ratio (for you b=1/2) and n= the number of term in your sequence (for you n=5, but it can be any number you want to find the nth sequence of.) Now take the equation a(n)=a(b)^n-1 and plug in your variables- Now your equation is a(5)=-14(1/2)^5-1 The first step to solving this is simplifying your exponent- so subtract 1 from five then your equation would read a(5)=-14(1/2)^4 Now solve the exponent then you would have a(5)=-14(1/16) then all you have to do is multiply a(5)=-7/8 So the fifth term in your sequence is -7/8 I hope this helped. :)

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Each term seems to be double of the previous number starting with 3. Hence 4th term = 24 and 5th is 48

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no it is the 3rd

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U5 = a + 5n = 4 U7 = a + 7n = 10 Therefore 2n = 6 and so n = 3 and then a = 4 - 5n = 4 - 15 = -11 So Un = -11 + 3n and therefore, U10 = a + 10n = -11 + 10*3 = -11 + 30 = 19

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