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Q: What is the sum of the first ten whole numbers that are multiples of two?

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The sum of the first 1,000 whole numbers is 499,500.

The sum of the first five whole numbers is 10.

The sum of the first 14 in whole numbers is 91.

The sum of the first 10 odd whole numbers is 100.

The sum of the first 50 whole numbers is 1,225.

The sum of the first 1,000 whole numbers is 499,500.

The sum of the first 40 whole numbers is 780.

The sum of the cubes of the first 100 whole numbers is 25,502,500.

The sum of the first 30 even whole numbers is 30(31) or 930

The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900

The sum is 10,000.

You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m

If the sum of their digits is a multiple of three, the whole number is a multiple of three.

The sum of two numbers is a whole number if both of the numbers are whole numbers, or if the sum of two fractions can be simplified to a whole number.

The sum of the first 1,000 integers (whole numbers) is 499,500.

The sum of the first 10 multiples of 3 is 165.

The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.

We have to assume that you're talking about whole numbers. The sum is 5,050 .

16

141,000

900

No. Odd numbers can be written as the sum of consecutive integers, but some multiples of odd numbers are even.

The sum of the first 5,000 odd numbers 25,000,000.

Their sum is 1200.

900