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The sum of the exterior angles of a polygon is 360o

If the exterior angle of a regular polygon is 72o, then:

number_of_sides x 72o = 360o

⇒ number_of_sides = 360o ÷ 72o

= 5 sides

total_of_interior_angles = (number_of_sides - 2) x 180o

= (5 - 2 ) x 180o

= 540o

Alternatively for the second half once the number of sides is known:

interior_angle = 180o - exterior_angle

= 180o - 72o

= 108o

total_of_interior_angles = number_of_sides x interior_angle

= 5 x 108o

= 540o

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Q: What is the sum of the interior angles of a regular polygon if each exterior angle measures 72?
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