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Q: What is the sum of the measures of the interior angles of a convex?

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The sum of the interior angles is 360.

The relevant formula for the sum of the interior angles of a convex polygon is (n - 2)(180) degrees, where n is the number of sides. In this instance, 180 n - 360 = 1260, or 180n = 1620, or n = 9.

1440 degrees

360 degrees (this is true with any convex polygon)

The interior angles of a 12 sided dodecagon add up to 1800 degrees

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the sum of the interior angles of a 35-gon.

3,600°

520 Degrees

5040

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6120 degrees

for novanet - 9,540

Hmmm... how bout 360 degrees ?

9540 degrees

The sum of the interior angles of any polygon of n sides is equal to 180(n - 2) degrees.

The sum of the exterior angles of any convex polygon is always 360 degrees. The sum of the interior angles of any convex n-gon is (n-2) * 180 degrees, because any convex n-gon can be represented as n-2 triangles, and the sum of the interior angles of a triangle is 180 degrees.

What is the sum of the measures of the angles of a convex quadrilateralwill this property hold if the quadrilateral is not convex?

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