The square root of 100 = 10 The square root of 225 = 15 The sum = 10 + 15 = 25
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
the answer is actually 29 because ask your teacher he'll ive you the work <3 Answer: PEMDAS-order of operations The square root of 100 is 10. The square root of 225 is 15. The sum of 10 + 15 is 25. The product of 6 and 25 is 250.
to find the root-sum square of n numbers you square each number, add them, then take square root of sum For exanple root sum square of 2,3, and 4 is square root of (4+9+16) = sqrt(29) = 5.39
You can. Just add the numbers together, and find their square root. One plus three is four; the square root of the sum is two.
Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...
The complex conjugate pair, 4.5 Ã‚Â± 14.3091*i (approx) where i is the imaginary square root of -1.
No. The right hand side is always greater - unless both components are zero.
because ur supposed to do it thAt way buddy
When you have calculated the square root of each number, simply add the results together and you will have the answer.
It is irrational.
Assuming the roots are positive, then ~ 15.59.
i think its 5000
It's an example of "addition".The sum is: 2 sqrt(34) .
VRMS = 1/N times square root of [ sum(Vn2) ]
The numbers are: 26 -square root of 524 and 26 +square root of 524
The four possible answers are +/- 18 or +/- 22.
No. The Square root of x is not the value of x. So it can not be simplified beyond: Root X + root 3x Yes. The square root of 3x equals the square root of 3 times the square root of x, so when you add another square root of x, you can factor out the square root of x, thereby simplifying the expression to the square root of x times the sum of one plus the square root of three.