I have also got 32, by 6+6+7=19-1=18, then 50-18 = 32
If you can use the numbers multiple times, then 50 * (1+7) = 50*8 = 400 and 400 / 6 = 66.666, then 6/6 = 1 + 1 = 2, then 66.666 / 2 = 33.333
By adding 5+1 to get the sum of six.
Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)
No. 2 is the only even prime number, and if you add an even number and an odd number, the result will always be odd.
to find the numbers between two numbers use this formula and reblace the a with the smaller number and b with the larger number((b^2+b)/2-b)-((a^2+a)/2)so the answer is 135 not including 20 as part of the sum
use the numbers 1-9 arranging them so the sum is correct for the two addends
When you say "sum", it means at least two numbers piled together.If you can only use one number, then the only number that can give you 7 is 7.
No. No matter what you use, the sum of an odd number and an even number will always be odd.
By adding 5+1 to get the sum of six.
Usually you use the word "sum" to add two or more numbers, not just one number. Of course, the sum of a single number is just the number itself.
Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)Use the definition of a perfect number! Add the factors; if the sum of all the factors (excluding the number itself) is equal to the number, it is a perfect number, otherwise it isn't. (Actually, the only perfect numbers less than 100 are 6, and 28.)
No. 2 is the only even prime number, and if you add an even number and an odd number, the result will always be odd.
to find the numbers between two numbers use this formula and reblace the a with the smaller number and b with the larger number((b^2+b)/2-b)-((a^2+a)/2)so the answer is 135 not including 20 as part of the sum
use the numbers 1-9 arranging them so the sum is correct for the two addends
No.
To find the sum of a set of numbers, you can use this formula: ∑ = (x)(x+1)/2 That is..... The sum = (The number of samples)(The number of samples + 1)/2 Example: What is the sum of all numbers between 500 and 1000? Assuming that we do not include 500 or 1000 in our answer, we have 498 numbers to add up. Let's put that into the formula.... ∑ = (498)(498+1)/2 ∑ = (498)(499)/2 ∑ = (248,502)/2 ∑ = 124,251 The Answer is 124,251
If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128
you can use whole numbers