4x5=20 therfore 20 square metres
Each triangular face is 25 sq.m.
Therefore the total surface area of the four triangular faces = 100 square metres.
If the square base has to be included, add another 25 square metres.
The surface area is a function of the height (or slant height) and the radius of the base. So, the slant height is a function of the surface area and the base-radius. Since the latter is unknown, the slant height cannot be calculated.
No, the slant height is the from the top vertex to the base of the base of the pyramid, it forms a 90 degree angle with the base and slant height. The lateral edge is literally the lateral (side) edge.
It is not possible to answer the question because the shape of the base is not known. As a result the surface area of the base, and hence the total surface area cannot be calculated.
Curved surface area = pi*radius*slant length = 792 square cm radius = 792 divide by (pi*slant length)
A slant height of 20 and base circle radius (r) of 20 gives slant length (s) = 28.284 equation for cone surface area : (pi * r * s) + (pi * r2) = 1777.136 + 1256.637 = 3033.773 units2
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
120
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
It is 9180900 square inches.
The slant height will be 25 cm
72 cm square.
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm is: 64 cm3
It is 125 square units.
It is the lateral area (which is 1/2 the perimeter multiplied by the slant height), plus the area of the base.
This pyramid would have a perpendicular height of 3, a volume of 64 units3 and a slant edge of 6.403
The slant height of a square pyramid is always perpendicular to the base. It is form the top vertex all the way down to the most center of one side of the base edge.