Use Pythagoras:
diagonal² = length² + width²
→ diagonal² = (10 cm)² + (15 cm)²
→ diagonal = √(10² + 15²) cm
= √325 cm
= 5 √13 cm
≈ 18 cm
It is approx 18.03 cm.
The formula to calculate perimeter of a rectangle is P=2L+2W P= 2(15) + 2(10) P= 30 +20 P = 50
Perimeter of rectangle: 2*(20+15) = 70m
To find the area of a rectangle, multiply the length by the width. 3 x 5 = 15. Do not forget to include the units, however - if the units of the rectangle are in inches, then the answer to the question will be 15 inches squared (15 in2).
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
Area = length x width, so the area of this rectangle would be 15 feet x 9 feet which equals 135 square feet.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The diagonal is about 28.3 feet.
15 cm for the diagonal.
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
The length is 20 cm.
A 9 x 12 rectangle has a diagonal of 15.
15 inches (solved with the help of Pythagoras' theorem)
15 cm Solved through Pythagoras' theorem.
120 feet
length of diagonal of 20 of a 20 feet and 15 width.
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length = √[152 + 82 - 2(15)(8)cos 100⁰] diagonal length ≈ 18 The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length =√[152 + 82 - 2(15)(8)cos 80⁰] diagonal length ≈ 16