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1st equation: 5x +7y +29 = 0 or 5x +7y = -29

2nd equation: 11x -3y -65 = 0 or 11x -3y = 65

Times all terms in the 1st equation by 11: 55x +77y = -319

Times all terms in 2nd equation by 5: 55x -15y = 325

Subtract the 2nd equation from the 1st equation: 92y = -644 or y = -7

By means of substitution point of intersection is made at: (4, -7)

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Q: What is the the point of intersection of the equations 5x plus 7y plus 29 equals 0 and 11x -3y -65 equals 0?
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