14 diagonals
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
It works out that a polygon with 1175 diagonals has 50 sides
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
It has 20 diagonals
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
The formula is: 0.5*(n2-3n) whereas n is the number of sides So: 0.5*(352-105) = 560 diagonals
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon
It works out that a polygon with 1175 diagonals has 50 sides
if a polygon has 560 diagnose how many vertices does it have
There are two diagonals in a trapezoid.
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
1. Number of diagonals = 0.5*(n2-3n) where n represents the number of sides2. If a polygon had 8 sides write out the numbers in descending order leaving out the first 2 numbers and the last number and adding them up gives the amount of diagonals:-6+5+4+3+2 = 20 diagonalsIf it had 9 sides then do the same:-7+6+5+4+3+2 = 27 diagonals