Q: What is the nth term in this sequence 18 23 28 33 38?

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58

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

All you have to do is add 5 each time(x+5) It's 43

It is: 5n+3 and so the next term is 28

It is: 27-2n

5, 11, 17, 23, 29

The sequence is 2 larger than the 7 times table. The nth term can be expressed as 7n + 2.

Un = 5n - 2

The nth term is 3(n+1). The twenty-third term is equal to 3 x (23 + 1) = 72

the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)

2n +29

Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.

If you meant: 2 12 22 32 then the nth term = 10n-8

t(n) = 5 - 7n for n = 1, 2, 3, ... The difference between each term is -7, therefore the nth term will be: t(n) = -2 + -7 × (n - 1) = -2 + 7n + 7 = 5 - 7n

35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1

An=A1+(n-1)d d= 23-18= 5 A1=18A21 = 18+(21-1)*5 = 118

It is: 10n-7 and so the next term is 43

It is: 9n+5 and so the next term is 50

14+9n

The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2

Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...

the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps

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