There is NO single value (THE vallue) for 2m when m takes three different values.
1/m + 1/2m = 6 LCD is 2m (2 + 1) / 2m = 6 3/2m = 6 3/6 = 2m = 1/2 m = 1/4
-1/2m = -9 To solve this: Multiply by 2m: -1 = -9*2m Divide by -9: -1/-9 = 2m Divide by 2: (-1/-9)/2 = m Work it out: -1/-9 = 0.111... (the 1 is recurring) 0.111... / 2 = 0.0555... (the five is recurring) So x = 0.055... or 5/90
8 - 2m = 2 so 6 = 2m or m = 3.
2m =200cm 1/2 x 200cm = 100cm
2m + 2 = 3m + 4 => 2m-3m = 4-2 => -m = 2 => m= -2
1/m + 1/2m = 6 LCD is 2m (2 + 1) / 2m = 6 3/2m = 6 3/6 = 2m = 1/2 m = 1/4
Kinetic energy = 1/2 (mv)2 if m increase by 2m, then Kinetic increases by 2
-1/2m = -9 To solve this: Multiply by 2m: -1 = -9*2m Divide by -9: -1/-9 = 2m Divide by 2: (-1/-9)/2 = m Work it out: -1/-9 = 0.111... (the 1 is recurring) 0.111... / 2 = 0.0555... (the five is recurring) So x = 0.055... or 5/90
8 - 2m = 2 so 6 = 2m or m = 3.
2m =200cm 1/2 x 200cm = 100cm
2m + 2 = 3m + 4 => 2m-3m = 4-2 => -m = 2 => m= -2
-2m + 7 = m - 2 +7 +2 = m +2m 9 = 3m 3m = 9 m = 9/3 = 3 to test: -2(3) + 7 = (3) - 2 -6 + 7 = 3 - 2 1 = 1
No, 2m=200cm
0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18
3.
M= 2.
m=34/2 which is 17