-10
(e3.50t - t2)/(1 + t4)
The third law could be expressed as: If T1 = T2 and T2 = T3, then T1 = T3. Where T1 is the temperature of system (or object) 1. T2 is the temperature of system (or object) 2. T3 is the temperature of system (or object) 3. That may seem trivial from an algebraic standpoint but it has profound implications in thermodynamics because it helps define the meaning of temperature and thermal equilibrium.
That's really very easy, because [ 12t3 - 48t ] isn't a question, so there's no answer needed.All it is is a number, whose value depends on the value of 't'.If your class is working on factoring, then the teacher may give you this expression andask you to factor it. If that's what's happening, then [12t3 - 48t] is not the question.The question is: "What is [12t3 - 48t] in factored form ?" That would be12t (t2 - 4)
The ratio of the quantity between two sets of time an equal period apart are the same. That is, the rate of growth over the same time is a constant. Suppose V(t) is the value of the variable V at time t. Then, if t1, t2, t3 and t4 are four times such that t2 - t1 = t4 - t3 then V(t2)/V(t1) = V(t4)/V(t3) whether V is compound interest or exponential growth.
(4x - t2)= [(2√x)2 - t2] (This is now the difference of squares)= (2√x - t)(2√x + t)
(e3.50t - t2)/(1 + t4)
= 1 - qout/qin = 1 - cv(T4-T1)/(cv(Tx-T2)+cp(T3-Tx))
The third law could be expressed as: If T1 = T2 and T2 = T3, then T1 = T3. Where T1 is the temperature of system (or object) 1. T2 is the temperature of system (or object) 2. T3 is the temperature of system (or object) 3. That may seem trivial from an algebraic standpoint but it has profound implications in thermodynamics because it helps define the meaning of temperature and thermal equilibrium.
^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]
Type your answer here... it is a T2 hyperintense foci
To derive a value for thermal coefficient of resistance, I find the resistance R1 at one temperature T1, and the resistance R2 at temperature T2. I can then express this coefficient as (R2 - R1) / [R1 (T2 - T1)] X 100% per degree. Example: R1 = 50 ohms at T1 = 20 degC R2 = 20 ohms at T2 = 500 degC (R2 - R1) / [R1(T2 - T1)] X100% per deg = (20 - 50) / [50 (500 - 20)] X100% per deg = - 0.125% per degC But this assumes the change in resistance is linear. In fact, such changes often happen on a curve. To estimate the form of the curve, at least three temperature:resistance data pairs are needed.
That's really very easy, because [ 12t3 - 48t ] isn't a question, so there's no answer needed.All it is is a number, whose value depends on the value of 't'.If your class is working on factoring, then the teacher may give you this expression andask you to factor it. If that's what's happening, then [12t3 - 48t] is not the question.The question is: "What is [12t3 - 48t] in factored form ?" That would be12t (t2 - 4)
Air
V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C
If you start on the G on the second line on the staff and then go to the G above the staff, the fingerings go like this: 0-T12-T2-T0-T12-T2-T2-T0-T2-T2-T12-T0-T2-T12-0 (G, A, B, C, D, E, F#, G, F#, E, D, C, B, A, G)
On the golf score board, the designation "T2" means tied for second place.
win the stick t2 tournament, as strange as that may seem