The discriminant of a quadratic ax2 + bx + c is b2 - 4ac; thus:
the discriminant of -9x2 + 6x + 14 is
62 - 4 x -9 x 14 = 540
The discriminant is 0.
It is zero because: 182-4*9*9 = 0
x=5
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
It is: 122-4*(9*-2) = 216
The discriminant is 0.
It is: 0
The discriminant is 0.
It is zero because: 182-4*9*9 = 0
x=5
9x2 - 12x + 4 = 0 is of the form ax2 + bx + c = 0 where the discriminant, D, can be found by D = b2 - 4ac First, you find the values of a, b and c: a = 9 b = -12 c = 4 Now you can find D: D = (-12)2 - (4)(9) = 144 - 36 = 108 D = 108
If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
It is: 122-4*(9*-2) = 216
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375
so 9x2 = -16. Doesnt work without going to imaginary numbers, x2 = -16/9 ie x = 4i/3