Variance = sigma((value - mean)2) / (# values - 1) Mean = (0+1+1+2)/4 = 1 Variance = ((0-1)2+(1-1)2+(1-1)2+(2-1)2)/(4-1) Variance = (1+0+0+1)/3 Variance = 2/3 Variance ~ 0.667
0.666666666667
z-scores are distributed according to the standard normal distribution. That is, with the parameters: mean 0 and variance 1.
It is a normal curve with mean = 0 and variance = 1.
le standard normal distribution is a normal distribution who has mean 0 and variance 1
The sample variance is obtained by dividing SS by the degrees of freedom (n-1). In this case, the sample variance is SS/(n-1) = 300/(4-1) = 300/3 = 100 In order to get the standard error, you can do one of two things: a) divide the variance by n and get the square root of the result: square.root (100/4) = square.root(25) = 5, or b) get the standard deviation and divide it by the square root of n. 10/square.root(4) = 10/2 = 5
The variance is: 0.666666666667
0.666666666667
Average = (0+0+1+2+3)/5 = 1.2 Variance = 1/N * SUM (x-E(x))2 = 1/5 * 6.8 = 1.36 Answer: Variance = 1.36
z-scores are distributed according to the standard normal distribution. That is, with the parameters: mean 0 and variance 1.
Z is a variable with mean 0 and variance 1.Z is a variable with mean 0 and variance 1.Z is a variable with mean 0 and variance 1.Z is a variable with mean 0 and variance 1.
Variance
Given a set of n scores, the variance is sum of the squared deviation divided by n or n-1. We divide by n for the population and n-1 for the sample.
Mean = 2. Variance = 1.
2.12.12.12.1
It is a normal curve with mean = 0 and variance = 1.
Program in CHere is a program in C to calculate mean variance and standard deviation: #include#includevoid main(){float a[50],sum=0,vsum=0,mean,variance,sd;int n,i;printf("Enter the no of valus");scanf("%d",&n);printf("Enter the no of valus");for(i=0;i
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