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What is the vertex for the parabola y equals x squared plus 4x plus 5?
Wiki User
∙ 8y ago
The vertex of a parabola is the minimum or maximum value of the parabola.
To find the maximum/minimum of a parabola complete the square:
x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1
As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie
(x + 2)² = 0
→ x + 2 = 0
→ x = -2
As (x + 2)² = 0, the minimum value is 0 + 1 = 1.
Thus the vertex of the parabola is at (-2, 1).
Wiki User
∙ 8y ago
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7
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What is the vertex of a parabola whose equation is y equals x 32?
The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?
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Question can be taken as multiple meanings. Please see discussion.
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The vertex is at the point (0, 4).
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What is x squared minus 8x plus 8y plus 32 equals 0 in standard parabola form?
7
What is the y value of the maximum y equals -x2 plus 6x-7?
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How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
What are the coordinates of the minimum point of a porabola whose equation is y equals x squared plus three?
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