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Q: What is the vertex of the parabola y equals 2x squared plus 12x 13?

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The minimum value of the parabola is at the point (-1/3, -4/3)

The vertex has a minimum value of (-4, -11)

It is the equation of a parabola.

Question can be taken as multiple meanings. Please see discussion.

The vertex of the positive parabola turns at point (-2, -11)

The vertex is at the point (0, 4).

It is a parabola with its vertex at the origin and the arms going upwards.

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By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero

20 and the vertex of the parabola is at (3, 20)

Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.

The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).

The given equation is not that of a parabola.

(6, 40) and (-1, 5)

The points at which the parabola intersects the x axis are 3-sqrt(10)/2 and 3+sqrt(10)/2. The X position of the vertex is in the middle, at 3. The y position, from there, is simply found by substituting 2 for x in the equation. As a result, the vertex is at (3, 5).

The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).

y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.

Parabola: 1+12x-6x^2 Factorizing: -6(x^2 -2x -1/6) Completing the square: -6((x-1)^2 -1 -1/6) => -6(x-1)^2 +7 Vertex of parabola is at: (1, 7)

It works out exactly as: 7 times the square root of 26

A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.

The solution comprises every point on a parabola which is symmetric about the y axis and has its apex at (0,1).

X equals 0.5at squared is a quadratic equation. It describes a parabola. Y equals mx plus b is a linear equation. It describes a line. You cannot describe a parabola with a linear equation.

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The vertex is at (-1,0).

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