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Y = X2 - 4X + 12

set to 0

X2 - 4X + 12 = 0

subtract 12 from each side

X2 - 4X = - 12

now, take the linear term ( - 4 ), halve it, square it and add it to both sides

X2 - 4X + 4 = - 12 + 4

factor the left side, gather terms on the right

(X - 2)2 = - 8

add 8 to each side

(X - 2)2 + 8 = 0

------------------------

(2, 8)

------------the vertex of this function

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12y ago
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Q: What is the vertex of the parbola y equals x2-4x plus 12?
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