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Q: What is the voltage if R equals 7 ohms and I equals 2 amps?
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What is the voltage if R equals 6 ohms and you equals 2 A?

E = I R = (2) (6) = 12 volts


What is the voltage if R equals 11 ohms and you equals 2 A?

Resistance = 11 ohmsCurrent = 2 amperesVoltage = 22 volts


What is the voltage if R 5 ohms and you 2 A?

voltage = resistance x current = 5 x 2 = 10 volts


What are two parts of kilowatt hour ammeter?

Most important part is the shunt. It diverts most of the current around the meter. They used to be 50 micro amp meter movements. They were 100 microamp movements with a resistor that matched the meters coil resistance and split the meter current. That is they fully deflect when 50 microamps is flowing through the coil of the meter movement. Electronic ones still have a shunt. It is basically a piece of metal used as a resistor. The resistors value determines the amount of current it will pass according to Ohms law. The full range current used in the calculation. "Amps equals voltage divided by resistance". "Resistance equals voltage divided by current". That would give you the full resistance. You calculate the 50 microamps and subtract its resistance and use the remainer as your shunt value. Part 1: Shunt Part 2: Meter That is an ampmeter. A watt meter is a combination of an ampmeter and a voltmeter. Ohms' Law applies strictly. You feed the amps and voltage to the meter movement ( now LCD display) and it "does the math" and displays in watts. Curent in amps is measured is series and volts are measured in parallel with the source. Voltage times amps equals watts. One kilowatt at standard household voltage of 115 volts A.C. is about 9 amps.


Ct equals .15uf Xc equals 636.9 ohms?

Nice data. What's your question ?Could you possibly be asking for the frequency ???Xc = 1 / (2 pi f C)f = 1 / (2 pi Xc C)= 106 / (2 pi Xc 0.15)= 106 / (600.264)= 1665.9 Hz (rounded)

Related questions

How do you calculate ohms?

Very basically, simply divide the voltage by the amperage. Thsi is not for calculating Ohms of resistance, just Ohms. For example, a 9 volt battery that delivers 3 amps has 3 ohms. To calculate ohms of resistance we use the ohms law. This measures the difference in current flow in amps (amps/current is amount or volume of flow, volts is power pushing that current, sort of) and voltage. For instance, measure the amps and voltage at the source and record the ohms. Then record the same at the end point the difference in ohms is ohms of resistance. So, if we measure 10 volts and 2 amps at the source we have 5 ohms. at the end point we have 8 volts and 1 amp we have 8 ohms. therefore we have 13 ohms of resistance. 1 Determine current. Current is the flow of electricity measured in amps. For example a current has four amps in the circuit. 2 Determine voltage. Voltage is the difference in electrical potential from two points, measured in volts. For example, there is two-hundred volts in a circuit. 3 Divide voltage by current to calculate resistance. Resistance is measured in ohms. In the example, two-hundred volts divided by four amps equals fifty ohms. 4 To get ohms of resistance, measure the end point. at the endpoint we have 100 volts and 2 amps=50 ohms. therefore we have 100 ohms of resistance


What is the current in a copper wire that has a resistance of 2 ohms and is connected to a 9-volt electrical source?

Current equals Voltage divided by Resistance. 9/2=4.5 amps.


What is the voltage drop through a resistor of 6 ohms (2 amps)?

12 volts


What is the voltage if R equals 6 ohms and you equals 2 A?

E = I R = (2) (6) = 12 volts


How much voltage is required to make 2 amperes flow through resistance of 8 ohms?

Ohm's Law: voltage is current times resistance, so 8 amps times 2 ohms is 16 volts.


What is the voltage if R equals 11 ohms and you equals 2 A?

Resistance = 11 ohmsCurrent = 2 amperesVoltage = 22 volts


What is the voltage of a circuit in a toaster with 12.0 amps of current and 8.0 ohms of resistance?

The formula you are looking for is Ohm's Law. Voltage = Current x Resistance (v = I x R). To solve for Current the formula is I = V/R.


Two resistors are connected in a parallel to a batterywhat is the voltage across these two resistors?

The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.


2 volts divided by 100 kOhms equals how many milliamps?

2 volts across 100 kOhms produces 0.02 milliamps (or 20 microamps) of current. Ohm's law: Voltage = Amperes * Ohms, so Amperes = Voltage / Ohms.


How much voltage does a line with resistance of 10 ohms and a current of 20 amps?

V = i*r v = 2 * 60 v= 120v


What voltage is needed to produce a current of 2 amps through a resistance of 6 ohms?

Where: V = Voltage (Volts), A = Current (Amps) and R = Resistance, (Ohms)Here are a few easy and related equations.V = A * RR= V / AA = V / RSo we have R=3 and A =6 and using the V=A*R equation we getVolts = A(6)*R(3) = 18 Volts.


Can you connect 2 amps to run a subwoofer?

If your sub is 2 ohms and your amp is 2 ohm stable, your done. Your amp will be at 2 ohms because the sub is 2 ohms.