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Q: What is the volume of a cone with the radius of 2 and height of 19?

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The volume of a cone with the radius of 3 and height of 19 is: 179 cubic units.

A cone with a base radius of 2 units and a height of 19 units has a volume of 79.59 cubic units.

The volume is 179.09 units3

79.59 units3

Volume of a cone = 1/3 * pi * r2 * h = 179.071 cubic units

Radius of cone = 19/2 = 9.5 mm Volume = (1/3) PI r^2 h, where r is the radius and h is the height, We need to know the height of the cone to find its volume.

Volume = 1/3*pi*22*19 = 79.587 cubic units to 3 decimal places

First, you will multiply the height (19) by Pi. (approximately 59.6902604165) Now, you will square the radius (3) to get 9. Then, you multiply 59.6902604165 by 9 to get approximately 537.2123437485. Then, you divide this by 3 to get the volume, which gives you approximately 179.0707812495units3.

i need the height dude what is the height?

If you visualize the cone by cutting it vertically (with a plane perpendicular to the base), you can construct a right triangle to represent the radius, altitude, and slant height. This triangle has legs of 7 (the radius) and 19 (the altitude). Its hypotenuse represents the slant height. We can then use the Pythagorean theorem to solve for the slant height: 72 + 192 = s2 72 + 192 = s2 410 = s2 s = √(410) s ≈ 20.24 Therefore the cone has a slant height of √(410), or approximately 20.248456731316586933246902289901 units.

The surface area of a cone if the height is 21 and the diameter is 19 is 971.43 units2

Is the height in inches, feet, yards? This question cannot be answered without knowing the unit for the height.

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