The volume of a cube is the side cubed, so a cube with a side length of 4 has a volume of 43 = 64.
The volume of a cube whose side length is 4 cm is: 64 cm3
Answer in short: cube root of volume. Side length of a cube is the cube root of the volume of the cube or the square root of the area of one of its sides. Examples: A cube of volume 64 has a side length of 4, and a side area of 16. A cube is a symmetrical three dimensional object.
If its volume is 64 cubic cm then its sides will be 4 cm
It is 4 m because 4*4*4 = 64 cubic m
There can be many volumes with only a length of 4 inches for a cube. the formula to find volume is volume=length x width x height. an example to find the volume of a cube with length 4 inches is, v=lxwxh v=4x2x3 v=8x3 v=24 inches cubed
A cube with a side length of 4 cm has a volume of 64 cubic cm.
The volume of a cube whose side length is 4 cm is: 64 cm3
The side length is the cube root of 64 which is 4.
Answer in short: cube root of volume. Side length of a cube is the cube root of the volume of the cube or the square root of the area of one of its sides. Examples: A cube of volume 64 has a side length of 4, and a side area of 16. A cube is a symmetrical three dimensional object.
The volume of the cube is the third power of the side length. For example, if the length of a side is 4 cm, then the volume is 4 cm x 4 cm x 4 cm = 64 cubic centimeters.
4 units of length
4 cm
Volume of cube = (side length )3 Volume of a sphere = 4/3*pi*r3 Looks like the sphere by a long shot, but let's see. Volume cube = (4)3 64 === The sphere has more volume.
The volume of a cube equals its side length cubed. In this case it is 4 inches3 which gives a volume of 64 cubic inches.
In a cube the length width and height are all the same so the volume of a cube is s3 where s is the length of a side. In this case, that is (4 cm)3 = 64 cm3
It is: 4*4*4 = 64 cubic units
The idea is to use the formula for the volume of a cube: V = s3 Where "V" is the volume, and "s" is the length of one side. Just replace the variable "s" with the actual length, and do the calculations.