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Q: What is the volume of a cylinder that has 15ft diameter and stands 22ft. tall?

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840 in (12 x 2 x (20 + 15))

More important, what is the question? Four different lengths do not define a rectangle.

area (A) = length (L) x width (W) = 54 L = W+15 so..... (W + 15) x W = 54 then W^2 + 15W = 54 putting it in a form (aX^2 + bX + C = 0) so that a quadratic formula (look it up on Widipedia) can be used to solve it: W^2 + 15W - 54 = 0 a=1, b = 15, c = -54 Solving give us W = 3, which means L = 18

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The volume would be pi*r^2*height =pi*(3.5ft)^2*15ft which gives an answer of 577.2676501 cubic feet.

V=Bh In this case: V="pi"r2h I can't understand your dimensions.

A circumference of 47.12 feet.

Volume: 3*15*2 = 90 cubic ft

I'm assuming you mean 30 feet diameter (from one side to another)? In that case: Calculate the volume of the cylinder (a round pool is a cylinder) using r = radius, which is half the diameter or 15ft = 15*12 = 180 inches h = 54 inches pi = 3.1415 180 * 180 * 54 * 3.1415 =5,496,368 cubic inches 1 gallon = 231 cublic inches so 5,496,368 / 231 = 23,793 gallons.

15ft is 5 yds, so 15ft x 15ft is the same as 5yds x 5yds which would equal 25 square yards.

The formula is pi*r^2, 30/2 is 15ft. 15x15x3.14159 is 706.86 sq ft

This is a volume requiring 11.1 cubic yards of cement.

Yes it will work with a 15ft HDMI cable

27

15ft X 52ft = 780 square feet.

22ft * 15ft = 330 sq ft = 30.658 sq metres

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