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Q: What is the volume of a right circular cone with a radius of 4 mm and a height of 6 mm?

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r = 0.41702

Volume of the cylinder: pi*radius*radius*height

V = 7,943 ft3

A right circular cone with a base radius of 3 ft and a height of 9 ft has a volume of: 84.8 cubic feet.

The volume is 141.37 cubic meters.

The volume is 47.12 cubic meters.

A cylinder with a radius of 3 meters and a height of 5 meters has a volume of 141.37 cubic meters.

108m3

volume of a regular right circular cylinder is V=pi(r2)h since the radius is (a) then the height of the circular cylinder would be (2a) so the volume of the largest possible right circular cylinder is... V=2(pi)(r2)(a) with (pi) being 3.14159 with (r) being the radius of the circle on the top and bottom of the cylinder with (a) being the radius of the sphere

V = (1/3) × (Π × r2 × h)Where, h = Height m = Slant Height V = Volume r = Radius of Base

Where slant height is 7ft and base radius is 4.5ft, the volume of a right circular cone will be 113.705 units cubed.

Volume = pi*r2*h = 87.9646 metres3 (to 4 dp)

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