(50g)/(15g/cm3)=3.333...cm3
or 3 1/3 cm3
Note 5cm isn't a volume it is a length therefore for the answer we are assuming the volume is 5cm3 Density = mass/volume Density = 15g/5cm3 = 0.015kg/0.000005m3 Density = 3g/cm3 or in SI units 3,000kg/m3
Ethanol (USP grade) has a density of 0.810. From here we have to use the formula: d=m/v, where d is density, m, mass and v, volume. Solving for volume, we have v=m/d, therefore: v= 15/0.810 = 18.52 mL of ethanol are equivalent to 15g.
Fluorine, at 19 atomic mass units, is the only halogen gas that fits that requirement.
800ml H2O10g Bacto-tryptone5g yeast extract10g NaClAdjust pH to 7.5 with NaOHAdd 15g agarMelt agar into solution in the microwaveAdjust volume to 1L with dH2OSterilize by autoclaving
That is about 2.9 teaspoons.
Density = Mass/Volume = 15/60 = 0.25 grams per millilitre.
Density = Mass/Volume = 15/10 = 1.5 g per mL
density = mass/volume = 15g/2mL = 7.5g/mL
Note 5cm isn't a volume it is a length therefore for the answer we are assuming the volume is 5cm3 Density = mass/volume Density = 15g/5cm3 = 0.015kg/0.000005m3 Density = 3g/cm3 or in SI units 3,000kg/m3
density = mass/volume = 150g/9.8cm3 =~15.3g/cm3 =~15g/cm3 (assuming volume of 9.8cm means 9.8 cubic centimeters)
15g/cm^3
m = mass rho = density V = volume rho = m/V m = rho * V = (15 g/cm^3) * (10 cm^3) = 150 g
Ethanol (USP grade) has a density of 0.810. From here we have to use the formula: d=m/v, where d is density, m, mass and v, volume. Solving for volume, we have v=m/d, therefore: v= 15/0.810 = 18.52 mL of ethanol are equivalent to 15g.
Denisty = mass / volume Density = 15g / 5cm3 Density = 3g per cm3 Once you know that the units of Density is g/cm3, you can use this to work out that you need to divide the mass (g) by volume (cm3) as can be seen in the units. This works for any equation you know the units for, like speed: Speed = m/s (meters/seconds) = distance/time
15g/cm3
15g/cm3
Before we can go on to find the density of the carbon nucleus, we must find its mass. The given molar mass, which is the mass of 1 mole of a substance, indicates there's 12.00 grams of carbon for every 1 mole of carbon. What the question wants to know is the density of 1 carbon atom. Before we proceed to finding the carbon atom's density, the mass for 1 carbon atom must be found. To achieve this, we must divide the molar mass by Avogadro's number (aka Avogadro constant), or how many molecules are in 1 mole of a substance.Mass per atom = molar mass/Avogadro's number= 12.00 g mol-1/6.02 x 1023 mol= 1.99 x 10-23gNow we can proceed to find the density of the carbon nucleus, since we now know the mass for 1 carbon atom.Density= mass/volume= 1.99 x 10-23g/9.9 x 10-39mL= 2.0 x 10-15g/mL OR 2.0 x 10-15g/cm31 mL is equivalent to 1 g/cm3, making these 2 units interchangeable.By the way, another way to write g mol-1 is g/mol (the -1 indicates the divisor or can be read as "per").