A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
The perimeter is 42 metres.
2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.
None. 42 yards is a length with no width. Therefore it cannot have a perimeter.
Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
The width is 24 feet.
There is insufficient information to answer this question. A rectangle with length L and width W has perimeter 2(L+W) So 2(L+W) = 42 which means L+W=21 So, given that the length should be greater than the width, any value of L such that 10.5 < L < 21 will meet the requirements. Obviously, for each value of L there will be a different value for W.
width = x and length = x+3 the perimeter = x + x +( x+3) +(x + 3) = 48, solve for x 4x + 6 = 48m 4x = 42 x = 10.5m (width) x+3 = 13.5m (length)
The perimeter of the rectangle is 42 units
L + W = P/2 = 42 ie L = 42 - W; L = 4W + 2 so 42 - W = 4W + 2 ie 5W = 40 so width is 8 cm making length 34 cm
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
Multiply the length by the width: 7 x 6 = 42. If the the units of length and width are metres (m) then the are would be metres squared (m2).
Perimeter of rectangle: 16.5+4.5+16.5+4.5 = 42 units
Area of rectangle: 6 times 7 = 42 square inches
Let the length be 2x+3 and the width be x: So: 2*(2x+3+x) = 258 => x = 42 feet Therefore: length = 87 feet and width = 42 feet Check: 2*(87+42) = 256 feet
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
what is the perimeter of a 11cm x 10cm rectangle answer 42
The width is 5.557 feet to 3 decimal places and its length is 7.557 feet to 3 decimal places
Length + width = ½ perimeter, ie 42 yards or 126 feet. L = 6 W so w = 126/7 = 18 feet and length is 108 feet ie 36 yards.
The perimeter of a rectangle = 2L + 2W So, from your problem we know that L = W + 27 Use this equation for the length and substitute in the perimeter equation, we get: 2(W+27) + 2W = 96 Now we rearrange and solve for W 2W + 54 + 2W = 96cm 4W + 54 -54 = 96 -54 4W = 42 W = 10.5cm, and using this value L = 10.5 + 27 = 37.5cm
42 <insert unit> squared.