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What is the width of a rectangle if length is 7 and perimeter is 42?
Wiki User
∙ 11y ago
Let w be the width, then 2(7 + w) = 42
or 14 + 2w = 42
or 2w = 42 - 14
or 2w = 28
w = 14
Wiki User
∙ 11y ago
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The length of a rectangle is 2 cm more than four times the width If the perimeter of the rectangle is 84 cm what are its dimensions?
L + W = P/2 = 42 ie L = 42 - W; L = 4W + 2 so 42 - W = 4W + 2 ie 5W = 40 so width is 8 cm making length 34 cm
If the perimeter of a rectangle is 96 cm. The length is 27 more than the width. What is the length?
The perimeter of a rectangle = 2L + 2W So, from your problem we know that L = W + 27 Use this equation for the length and substitute in the perimeter equation, we get: 2(W+27) + 2W = 96 Now we rearrange and solve for W 2W + 54 + 2W = 96cm 4W + 54 -54 = 96 -54 4W = 42 W = 10.5cm, and using this value L = 10.5 + 27 = 37.5cm
What is the largest and smallest perimeter possible for a rectangle with a area of 42?
Largest = 86, Smallest 26
If the perimeter of a regular heptagon is 42 how long is each side?
42/7 = 6 units of length.
The length of a rectangle is three times its width If the area of the rectangle is 147 what is its perimeter?
Write a a series of equations as follows p=2l+2w (formula for perimeter) a=l*w (Formula for area) l=3w (fact given in the question) a=147 (fact given in hte question) We don't currently have enough information to solve the perimeter formula for this rectangle, so we begin with the area formula to get more information. By substituteing 147 for the variable a and 3w for the variable l, we arrive at this equation: 147=w*3w With only one variable, we can solve this equation by isolating w on one side as follows 147=3w2(Multiply w by w to combine like terms) 147/3=3w2/3 (divide both sides by 3) 49=w2 sqrt49=sqrtw2(square root of both sides) 7=w We now know that the width of the rectangle is 7. We also know that the length is three times that, which is 21. We can substitute these values into the perimeter eequation as follows: p=(2*7)+(2*21) p=14+42 p=56 The perimeter of the rectangle is 56
What is the perimeter of a rectangle with length 42 inches?
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
What is the perimeter of a rectangle with a length of 14 meters and a width of 7 meters?
The perimeter is 42 metres.
If the length of a rectangle is twice the width the perimeter is 42 inches what is the width?
2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.
What is the perimeter of 42 Meters and length?
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
Rectangle ABCD has a perimeter of 112 inches If the width is 14 inches what is the length?
Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42
What happens to the perimeter of a rectangle when its length and width are quadrupled?
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
If the length of a rectangle is 3 meters more than the width and the perimeter of the rectangle is 48 meters?
width = x and length = x+3 the perimeter = x + x +( x+3) +(x + 3) = 48, solve for x 4x + 6 = 48m 4x = 42 x = 10.5m (width) x+3 = 13.5m (length)
What is the perimeter of a 9.5 inch by 11.5 inch rectangle?
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
What is the perimeter of 42 yards?
None. 42 yards is a length with no width. Therefore it cannot have a perimeter.
Length of a rectange is 5m greater than the width the perimeter is 84m2 what is the length and width?
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
The length of a rectangle is 5 cm what is its width?
42
What is the length and width of a rectangle with the perimeter of 42 inches?
There is insufficient information to answer this question. A rectangle with length L and width W has perimeter 2(L+W) So 2(L+W) = 42 which means L+W=21 So, given that the length should be greater than the width, any value of L such that 10.5 < L < 21 will meet the requirements. Obviously, for each value of L there will be a different value for W.
