Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
12x - 5 = 30Add 5 to each side:12x = 35Divide each side by 12:x = 35/12=======================y = 2x - 6Substitute the value of 'x' :y = 2(35/12) - 6Clear parentheses:y = 35/6 - 6y = 35/6 - 36/6y = -1/6
Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
( 8x2 - 14x - 30 ) divided by ( 2x - 6 ) = 4x + 5
36 - 21 + 15 = 30 36 - 21 - 15 = 0
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12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6
30+12x = 6(5+2x)
write it as 2 separate equations: 12x-5y=30 2x-6=30 Now the easiest thing to do is solve the second equation: 2x=36 x=36/2 x=18 Now just plug x=18 into the first equation: 12*18-5y=30 216-5y=30 -5y=-186 y=37.2
12x - 5 = 30Add 5 to each side:12x = 35Divide each side by 12:x = 35/12=======================y = 2x - 6Substitute the value of 'x' :y = 2(35/12) - 6Clear parentheses:y = 35/6 - 6y = 35/6 - 36/6y = -1/6
y = 5 - 2x so 4x + 6(5 - 2x) = -2 ie 4x + 30 - 12x = -2 Subtract 30 from each side: 4x - 12x = -32 ie -8x = -32 so x = 4 and y = -3
2x2 + 6 = 30 is your statement.2x2 = 24x2 = 12x = ±√12x = ±√(4*3)x = 2√3 or x = -2√3
Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
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12x-30=114 12x=114+30 x=144 / 12 therefore x=12
It is: 6(2x-5) when factorized
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It is: 6(2x-5) when factored