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There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.

Q: What is the y intercept and slope in this equation x equals -5?

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Slope: -2 Intercept: 5

y = 5x - 3

Slope = -6/5 = -1.2 y-intercept = -3

The slope is 1 and the y intercept is 5

If: x+y = 5 Then: y = -x+5 which is now in slope-intercept form

Related questions

Slope: -2 Intercept: 5

y = 5x - 3

Slope = -6/5 = -1.2 y-intercept = -3

Slope = -2 Y intercept = 5 =p

The slope is 1 and the y intercept is 5

If: x+y = 5 Then: y = -x+5 which is now in slope-intercept form

The given equation is : x + 5 + y = 0 Write in standard form of equation of straight line : y = mx + c . Where m is slope and c is y-intercept. We get: y = -x - 5 Which gives slope = -1 y-intercept = -5 To get x-intercept put y = 0 in the equation. We get x-intercept = -5

5

Since your equation is already in slope-intercept form, it's easy. Slope-intercept form is as follows: y=mx+b m always ends up being your slope, and b is your y intercept. Slope = 5, and the y intercept = 8 in your equation.

In the straight line equation of y = 3x+5 the slope is 3 and the y intercept is 5

y= slope + y-intercept

In order to find the slope and y-intercept we must first put the equation into slope intercept formula. This formula is y=mx+b where m=slope and b=y-intercept. Taking the equation 7x+2y=10 you can figure out the slope intercept formula of y=(-7/2)x+5. Given that information the slope is -7/2 and the y-intercept is 5.